BASH question

[Lennart Sorensen]

On Fri, Dec 21, 2007 at 12:15:24PM -0500, Dave Mason wrote:
> I wasn't aware of this new-fangled syntax:
> 
>     while ...; do
> 	...
>     done < <(ls -l)
> 
> but it does appear to work.  If you want something that works with older
> shells, you can do something like:
> 
> 	ls -l | (
> 	   while ...; do
> 		 x=...
> 	   done
> 	   ... $x ...
> 	   )
> 
> where everything in the () runs in a separate shell with stdin set to
> the pipe.

Of course since that one is a subshell, any variable you set in that
loop, won't be available to the main script.

Can't you just do:
ls -l | while ...; do
	x=...
done
... $x ...

Does it need a subshell?

--
Len Sorensen
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