bash $X++ sintax

Thu May 25 19:10:41 UTC 2006

On Thu, 25 May 2006, Neil Watson wrote:

> I just discovered that let "X++" works also but, I don't think that is 
> portable.

     No, it's not, See my previous message for details.

>  What about the perl
> operator .= ?

     What does that do?

-- 
    Chris F.A. Johnson                      <http://cfaj.freeshell.org>
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    Author:
    Shell Scripting Recipes: A Problem-Solution Approach (2005, Apress)
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