bash $X++ sintax

[Chris F.A. Johnson]

On Thu, 25 May 2006, Neil Watson wrote:

> What is the bash equivalent of the perl command
> $X++;

    If you mean to increment a variable, then the portable, POSIX way
    is:

X=$(( $X + 1 ))

    A little less portably, though still POSIX is:

: $(( X += 1 ))

    This works in bash, but is not POSIX compliant:

(( ++X ))

-- 
    Chris F.A. Johnson                      <http://cfaj.freeshell.org>
    ===================================================================
    Author:
    Shell Scripting Recipes: A Problem-Solution Approach (2005, Apress)
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