Doing a Linux MASS install.

Peter plp-ysDPMY98cNQDDBjDh4tngg at public.gmane.org
Thu Jul 20 19:44:48 UTC 2006


On Thu, 20 Jul 2006, Vlad wrote:

> On 7/20/06, Peter <plp-ysDPMY98cNQDDBjDh4tngg at public.gmane.org> wrote:
>> 
> [snip]
>> 
>> The IPs go like:
>> 
>> mother: 10.0.0.1, serves 10.0.0.10-19
>> 
>> child: 10.0.0.10, becomes 'mother' and serves 10.0.0.20-29
>> child: 10.0.0.11, becomes 'mother' and serves 10.0.0.30-39
>> ...
>> 
>> the rule is: server ip x.x.x.N -> will dhcp for 10*((N-10)+1)+0..+9
>> 
>> this covers it to 1+10+100 = 111 hosts, and you can't have more than
>> this on a network at the same time anyway so it should be enough.
>
>       Pardon? Uhm, if it's a /24, you can still have over twice that.

A single network segment won't support more than 256 hosts but 100 is 
about the limit ime. It would make a 100MBps segment feel like 1MBps 
adsl, at best.

>       Since you picked the "Class A" RFC1918 IP block, you can have
> about ~16,000,000 hosts on it, if you flatten it to 10.0.0.0/8. Better
> bring out that Cat6509 loaded with 48-port blades... ;)
>       Each server merely increments the third octet until it hits
> 255, and then the second octet, etc. Trust me, you won't run out of
> IPs.

That can be done too, but as I have said, it is just a suggestion.

Peter
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