Doing a Linux MASS install.

Vlad shiwan-Re5JQEeQqe8AvxtiuMwx3w at public.gmane.org
Thu Jul 20 19:00:57 UTC 2006


On 7/20/06, Peter <plp-ysDPMY98cNQDDBjDh4tngg at public.gmane.org> wrote:
>
[snip]
>
> The IPs go like:
>
> mother: 10.0.0.1, serves 10.0.0.10-19
>
> child: 10.0.0.10, becomes 'mother' and serves 10.0.0.20-29
> child: 10.0.0.11, becomes 'mother' and serves 10.0.0.30-39
> ...
>
> the rule is: server ip x.x.x.N -> will dhcp for 10*((N-10)+1)+0..+9
>
> this covers it to 1+10+100 = 111 hosts, and you can't have more than
> this on a network at the same time anyway so it should be enough.

        Pardon? Uhm, if it's a /24, you can still have over twice that.

        Since you picked the "Class A" RFC1918 IP block, you can have
about ~16,000,000 hosts on it, if you flatten it to 10.0.0.0/8. Better
bring out that Cat6509 loaded with 48-port blades... ;)
        Each server merely increments the third octet until it hits
255, and then the second octet, etc. Trust me, you won't run out of
IPs.

> To save time, the next bunch of 100 machines replace the 'last' layer.
> In the end the final install (second reboot) should revert to DHCP
> client mode.
>
> Peter
>
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