bash question

[William Park]

On Tue, Oct 05, 2004 at 10:28:59AM +0200, Peter L. Peres wrote:
> 
> I have asked this before: how does one expand parameters in bash for 
> indirection ?
> 
> Specifically:
> 
> foo=123
> bar=foo
> 
> now, what do I do to get the contents of foo knowing bar. I.e.:
> 
> baz=?!?(bar) such that baz=123
> 
> (find the ?!? operator, without using the name foo explicitly). I tried 
> various ${:=} etc expansions with no luck.

man bash
/indirect

-- 
William Park <opengeometry-FFYn/CNdgSA at public.gmane.org>
Open Geometry Consulting, Toronto, Canada
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