bash question

[Peter L. Peres]

I have asked this before: how does one expand parameters in bash for 
indirection ?

Specifically:

foo=123
bar=foo

now, what do I do to get the contents of foo knowing bar. I.e.:

baz=?!?(bar) such that baz=123

(find the ?!? operator, without using the name foo explicitly). I tried 
various ${:=} etc expansions with no luck.

Peter
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