GNU regcomp(3), regexec(3): '\w'

[John Wildberger]

The saga continues:
I compiled the test program on Debian kernel 2.4.14 with gcc ver 2.95.4
The value of a=0, b=7 and the result is as to be expected {abc_123}
John

On January 3, 2004 05:02 pm, John Wildberger wrote:
> On January 2, 2004 07:42 pm, Peter L. Peres wrote:
> > Eh ? Strange. I just recompiled with all warnings on:
> >
> > plp-NSb0HxlTAbs at public.gmane.org:~/PROJECTS/REGEXP > gcc -o r r.c -Wall --pedantic
> > r.c:9: warning: return-type defaults to `int'
> > r.c: In function `main':
> > r.c:28: warning: implicit declaration of function `strndup'
> > r.c:28: warning: format argument is not a pointer (arg 3)
> > r.c:30: warning: control reaches end of non-void function
> >
> > plp-NSb0HxlTAbs at public.gmane.org:~/PROJECTS/REGEXP > gcc --version
> > 2.7.2.3
>
> My compiler is gcc version 3.2.2
> I got similar warnings as above.
> The last one is easy to correct by just adding a return 0; at the end.
> The implicit declaration warning is usually an indication that the header
> is either missing or internally it is bypassed (defined __USE_GNU  ??) For
> what it is worth here are some comments:
> The printf() expects a number of 7 for b-a in order to give a result of
> {abc_123}
> To see what you have, introduce a printf("a= %d b=%d \n", a,b);
> ahead of your printf(..) . You will see that a=0, and b=4. This will give
> you the result {abc_} without  the missing 123.
> Maybe this will help.
> John
> --

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