(Fwd) Re:Bash Programming
Tim Writer
tim-s/rLXaiAEBtBDgjK7y7TUQ at public.gmane.org
Fri Aug 20 13:54:42 UTC 2004
"Paul King" <pking123-rieW9WUcm8FFJ04o6PK0Fg at public.gmane.org> writes:
> From: Paul King <pking123-rieW9WUcm8FFJ04o6PK0Fg at public.gmane.org>
> Subject: Re: [TLUG]: Bash Programming
> To: Devin Whalen <devin-Gq53QDLGkWIleAitJ8REmdBPR1lH4CV8 at public.gmane.org>
> Send reply to: pking123-rieW9WUcm8FFJ04o6PK0Fg at public.gmane.org
> Date sent: Wed, 18 Aug 2004 21:15:19 -0400
>
> > > Bash-2.05b supports array, as evidenced by Linux box. Your scripts runs
> > > okey here on 2.05b and 3.0.
> >
> > Ok...I ran it with ./file.sh and it worked fine!! What is the
> > difference between ./ and sh? I don't want to make the same mistake
> > again.
>
> sh script.sh
> runs the script as though the line
> #! /bin/sh
> were inserted at the beginning of the script.
This assumes /bin/sh is the first instance of sh in your PATH which is
usually but not always the case. If your PATH was:
/usr/local/bin:/bin:/usr/bin
and /usr/local/bin/sh exists and is executable, "sh script.sh" would be
equivalent to running "/usr/local/bin/sh script.sh".
> ./script.sh
> runs the script as if it has execute privelages and the line
> #! /bin/sh
> is inserted at the beginning of the script. In fact, script.sh should have
> execute privelages if it to be run this way.
Only if the script doesn't begin with "#!". IOW, the default behaviour (of
running the script with /bin/sh) is only activated if the script doesn't
already specify an interpreter via a "#!" first line. For example, if the
first line of the script was:
#!/bin/cat
running "./script.sh" is equivalent to:
/bin/cat ./script.sh
--
tim writer <tim-s/rLXaiAEBtBDgjK7y7TUQ at public.gmane.org> starnix inc.
905.771.0017 ext. 225 thornhill, ontario, canada
http://www.starnix.com professional linux services & products
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